## Answer 2.13

#### Let us assume that the link is a baseband link, that is, the frequency response extends from dc to 12 kHz.

1. For a baseband channel the symbol rate can be up to twice the available bandwidth, hence this channel can support up to 24000 symbols/second. With binary signalling, this is equal to a bit rate of 24 kbps.
2. The Shannon–Hartley equation gives us the required relationship between channel capacity in bps, bandwidth and signal to noise ratio as follows:
   Channel capacity C = B.log2(S/N + 1) bps
   Therefore C = 12.103log2(10000 + 1) bps = 159.45 kbps